Question

Find the speed of a train which leaves Secundrabad at 7 pm, and reaches Bhopal the next
day at a.m. It stops for 1 hour on the way. The distance between Secundrabad and Bhopal
6710 km. Also find the average speed correct to one place of decimal​

Answer 1

Step-by-step explanation:

Distance travelled = 710 km

Time taken = 10 hrs

We know Distance = speed * time

Speed = Distance /time

= 710/10 = 71 km/hr

Average speed = 71 km/hr

Answer 2

Answer:

Distance travelled = 710 km

Time taken = 10 hrs

We know Distance = speed * time

Speed = Distance /time

= 710/10 = 71 km/hr

Average speed = 71 km/hr

Step-by-step explanation: