Question

Find the speed of the electron in the ground state of a hydrogen atom

Answer 1

Now,

M base e = 9.12 × 10^–31 kg r = 0.53 × 10^–10 m

Now, Fe = M base ev^2/r ⇒ v^2 = Fe * r/m base e = 8.2 * 10^-8 * 0.53 * 10^-10/9.1 * 10^-31 = 0.4775 * 10^13 = 4.775 * 10^12 m^2/s^2

⇒ v = 2.18 * 10^6 m/s