Question

Find the sq . root by repeated subtraction of odd numbers , starting from .1



plz tell me its argent​

Answer 1

We know that
Square root of 121
121−1=120
120−3=117
117−5=112
112−7=105
105−9=96
96−77=85
85−13=72
72−15=57
57−17=40
40−19=21
21−21=0
So the square root of 121 is 11
Hence, 121 is a perfect square.

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