Question

find the sq root of -8-6i

Answer 1

$The \: \: answer \: \: is \: \: given \: \: below \\ \\ Now ,\: \: - 8 - 6i \\ \\ = (1 - 9) - 6i \\ \\ = 1 - 6i - 9 \\ \\ = 1 - 6i + 9 {i}^{2} \: \: (since, \: \: {i}^{2} = - 1) \\ \\ = 1 - 2 \times 1 \times 3i + {(3i)}^{2} \\ \\ = {(1 - 3i)}^{2} \\ \\ Hence, \: \: the \: \: required \: \: \\ square \: \: roots \: \: of \: \: ( - 8 - 6i ) \\ are \\ \\ + (1 - 3i) \: \: and \: \: - (1 - 3i). \\ \\ Thank \: \: you \: \: fo r\: \: your \: \: question.$

Answer 2

see in attachment

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