find the sqare root of 64x⁴-16x³+17x²-2x+1
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3
Answer:
x
4
−16x
3
+86x
2
−176x+105=0
Let the other two roots be a,b
S
1
=1+7+a+b=16
⇒a+b=8....
S
4
=7ab=105
⇒ab=15....
substituting b from (i)
a(8−a)=15
8a−a
2
=15
a
2
−8a+15=0
a
2
−5a−3a+15=0
a(a−5)−3(a−5)=0
(a−3)(a−5)=0
⇒a=3,5
substituting a in
⇒b=5,3
So the other two roots are 3 and 5
Step-by-step explanation:
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