Question

find the sqare root of (x-1)(x-2)(x²-3x+2)​

Answer 1

Step-by-step explanation:

x²-3x+2 = x²-x-2x+2 =x(x-1)-2(x-1)=(x-1)(x-2)

(x-1)(x-2)(x-1)(x-2) = sqrt (x-1)²(x-2)² = (x-1)(x-2)