find the sqrt of -2i
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Answer:
4
Step-by-step explanation:
(2)2=4
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√-2i
√-2i = a + bi
squaring both the side
-2i = (a + bi)²
-2i = a² + 2abi + b²i²
-2i = a² - b² + 2abi ...i² = -1
-2i = (a² - b²) + 2abi
Equating real and imaginary parts
a² - b² = 0 and -2i = 2abi
a² - b² = 0 ...(1) and ab = -1 •°• b = -1/a ...(2)
substituting in 1
a² - (-1/a)² = 0
a² - 1/a² = 0 •°• (a⁴ - 1)/a² = 0
a⁴ - 1 = 0 •°• a⁴ = 1 •°• a = 1 ....(3)
substituting in 2
b = -1/(1) = -1 •°• b = -1
•°• √2i = a + bi = 1 - i
•°• sqrt of -2i is 1 - i
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