Question

find the square (2x - 2y)
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Answer 1

$\left(2x-2y\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=2x,\:\:b=2y$

$=\left(2x\right)^2-2\cdot \:2x\cdot \:2y+\left(2y\right)^2$

$=4x^2-8xy+4y^2$