Question

find the Square....... ​

Answer 1

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To find :

The square of 102, using the identity :

$\bf (a + b)(a - b) = {a}^{2} + 2ab + {b}^{2} \\ \\ \bf Here \: let \\ \bf a = 100 \: \: \: \: and \: \: \: \: \: b = 2 \\ \bf then \: we \: get : \\ \\ \bf (100 + 2)(100 + 2) \\ \bf = (100)^{2} + 2(100)(2) + {(2)}^{2} \\ \bf = 10000 + 2(200) + 4 \\ \bf = 10000 + 400 + 4 \\ \bf = 10404$

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$\huge\bf{{\color{navy}{Hope}}~{\color{blue}{it}}~{\blue{helps..!!}}}$

Answer 2

$\tt{The \: square \: of \: 102, using \: the \: identity \: :}$

$</p><p></p><p>\begin{gathered} \bf (a + b)(a - b) = {a}^{2} + 2ab + {b}^{2} \\ \\ \bf Here \: let \\ \bf a = 100 \: \: \: \: and \: \: \: \: \: b = 2 \\ \bf then \: we \: get : \\ \\ \bf (100 + 2)(100 + 2) \\ \bf = (100)^{2} + 2(100)(2) + {(2)}^{2} \\ \bf = 10000 + 2(200) + 4 \\ \bf = 10000 + 400 + 4 \\ \bf = 10404\end{gathered}(a+b)(a−b)=a2+2ab+b2Hereleta=100andb=2thenweget:(100+2)(100+2)=(100)2+2(100)(2)+(2)2=10000+2(200)+4=10000+400+4=10404</p><p></p><p></p><p>$