Question

find the square area of a box whose length is 40 cm breadth 27 cm and height 10cm​

Answer 1

Answer:

10800

Step-by-step explanation:

40 times 27 times 10 equals 10800

hope it is correct

Answer 2

Correct Question:-

• Find the surface area of a box whose length is 40 cm breadth 27 cm and height 10cm.

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Given:-

• Length of box is 40 cm.
• Breadth of box is 27 cm.
• Height of box is 10 cm.

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To find:-

• Surface area of the box.

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Solution:-

★Formula used:-

→ TSA of Cuboid box = 2(lb + bh + hl)

→ 2(40 × 27 + 27 × 10 + 10 × 40)

→ 2(1080 + 270 + 400)

→ 2 × 1750

→ 3520 cm³

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Hence,

• the total surface area of the Cuboid box is 3520 cm³.

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☆More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$