Find the square by using identity
[2 m/3 + 3n/2)^2
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Answered by
0
Step-by-step explanation:
Using Identity,
(a+b)^2 = a^2 + b^2 + 2ab
Put,
a = 2m/3
b = 3n/2
(2m/3)^2 + (3n/2)^2 + 2(2m/3 + 3n/2)
4m^2/9 + 9n^2/4 + 4m/3 + 3n
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