Math, asked by karunarana218, 1 month ago

Find the square numbers lie between 11and 90​

Answers

Answered by UniqueOne07
1

Hint: To solve this problem, we will square the numbers given in the problem (that is 12 and 13). We will then enlist the numbers that lie between them. After then, we can count enlisted numbers.

We will first start by knowing the concepts of squaring a number before we begin to solve the problem. Basically, squaring a number means multiplying a number with itself to get a perfect square (a number which can be expressed as a square of any other number). For example, we have the following numbers (1, 2, 3 and 4). Now squaring them means multiplying these numbers by themselves, doing so, we get 1×1=11×1=1, 2×2=42×2=4, 3×3=93×3=9 and 4×4=164×4=16. Now, coming back to the problem in hand, we need to find the numbers that lie between squares of 12 and 13. Thus, we first find the squares of 12 and 13. We have, 12×12=14412×12=144 and 13×13=16913×13=169. Now, we need to find the numbers between 144 and 169. The numbers between 144 and 169 are 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160, 161, 162, 163, 164, 165, 166, 167 and 168. We can clearly see that there are 24 numbers (by counting the enlisted numbers).

Hence, there are 24 numbers that lie between the squares of 12 and 13.

Note: An alternative to find the numbers between two numbers say a and b, we use the formula given by (b-a-1). For example, in case of 144 and 169, we can find the numbers between them by using this problem. We have, (169-144-1) = 24.

Answered by ahilyakendre9462
8

Answer:

see natural numbers between 11square and 12squere is

11 { \: }^{2} = 121 \: \: and \: 12 {}^{2} = 14411

2

=121and12

2

=144

so now you have to minus from higher to lower

so

144 - 121 = 23144−121=23

but we shold not count last number so

23-1=22

so 22 natural number is there hey hope it will useful for you

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