Question

Find the square of (0.6x-0.7y)

Answer 1

hey mate here is ur answer


✔✔the identity that can be used

is

$(x - y)^{2} = {x}^{2} + {y}^{2} - 2xy \\ {(0.6x - 0.7y)}^{2} = {(0.6x)}^{2} + {(0.7)}^{2} - 2(0.6x)(0.7)y \\ = 0.36 {x}^{2} + 0.49 {y}^{2} + 0.84xy$
this is ur answer

hope this helps u

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