Question

find the square of 105 using identity (a+b)²=a²+2ab+b²​

Answer 1

Answer:

$\begin{gathered}\begin{gathered}\red{\Large{\underbrace{\underline{\bf{ \{GIVEN\::}}}}} \\ \end{gathered} \end{gathered}$

• (a+b)²=a²+2ab+b²
• find the square of 105

$\begin{gathered}\begin{gathered}\red{\Large{\underbrace{\underline{\bf{ \{solution\::}}}}} \\ \end{gathered} \end{gathered}$

$\sf \implies \: 105 = 100 {}^{2} + 5 {}^{2} + 2(100) \: (5) \\ \\ \sf \implies10000 + 25 + 1000 \\ \\ \sf \implies \boxed{ \bold{ \red{11025}}}$

Hence, This is Answer.

Answer 2

$\sf\huge\bold{Answer:}$

Given :

105

identity (a+b)²=a²+2ab+b²

To find :

Square of 105

Solution :

105 can be splitted as 100+5

Squaring 105 i.e (105)²=(100+5)²

Now, using given identity

$\boxed{\tt \red{ { (a + b) {}^{2} = {a}^{2} + 2ab + {b}^{2} }}}$

$\tt = (105) {}^{2}$

$\tt = (100 + 5) {}^{2}$

$\tt = (100) {}^{2} + 2(100)(5) + {5}^{2}$

$\tt = 10000 + 10 \times 100 + 25$

$\tt = 10000 + 1000 + 25$

$\tt = 11025$

$\boxed{ \huge\underline{ \purple{(105) {}^{2} = 11025}}}$