Find the square of 2n +1 by 2n
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Step-by-step explanation:
2n+1=k2
2n=k2−1=(k−1)(k+1)
n=(k−1)(k+1)2
LHS is always even so, RHS has to be even too.
So, either (k - 1) or (k + 1) has to be divisible by 2. In either case, k has to be a odd number for the above statement to hold true.
Thus, both (k - 1) and (k + 1) will be even.
So, lets say (k - 1) = 2a, then (k + 1) = 2a + 2
So, n=2a(2a+2)2=2a(a+1)
Now if a is odd then a+1 is even, and if a is even then a+1 is odd. In either case, we can get a factor of 2 out from them.
So, a(a+1)=2b
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Answer:
hi
Answer is a(a+1)=2b
Step-by-step explanation:
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