Find the square of (2x-5)
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Answer:
(2x-5)^2= (2x)^2 + (5)^2 - 2×2x×5 ((a-b)^2= a^2 +b^2 -2ab)
= 4x^2 + 25 - 20x
= 4x^2 -20x +25
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