find the square of (2y-3z)
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Answered by
2
Answer:
(2y-3z)² = (2y)² -2(2y)(3z) +(3z)²
= 4y² -12yz +9z²
hope it helps u....... ^_^
Answered by
0
Answer:
ur ans is 4y^2 - 12 yz + 9z^2
Step-by-step explanation:
( 2y - 3z )^2
identity that is applicable is ;
( a- b )^2 = a^2 - 2ab + b^2
here , a = 2y and b = 3a
(2y - 3z)^2 = (2y)^2 - (2)(2y)(3z) + (3z)^2
= 4y^2 - 12 yz + 9z^2
that ur ans ......thank u
hope this helps!!!
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