Math, asked by apoorv5167, 8 months ago

find the square of (2y-3z)​

Answers

Answered by Ishwarya12
2

Answer:

(2y-3z)² = (2y)² -2(2y)(3z) +(3z)²

= 4y² -12yz +9z²

hope it helps u....... ^_^

Answered by Anonymous
0

Answer:

ur ans is 4y^2 - 12 yz + 9z^2

Step-by-step explanation:

( 2y - 3z )^2

identity that is applicable is ;

( a- b )^2 = a^2 - 2ab + b^2

here , a = 2y and b = 3a

(2y - 3z)^2 = (2y)^2 - (2)(2y)(3z) + (3z)^2

= 4y^2 - 12 yz + 9z^2

that ur ans ......thank u

hope this helps!!!

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