Question

find the square of (3√2+2√5)​

Answer 1

Answer:

$\left(3\sqrt{2}+2\sqrt{5}\right)^2$

  Using formula, $\left(a+b\right)^2=a^2+2ab+b^2$

  Where, $a=3\sqrt{2},\:\:b=2\sqrt{5}$

$\left(3\sqrt{2}\right)^2+2(3\sqrt{2})(2\sqrt{5})+\left(2\sqrt{5}\right)^2$

$18+12\sqrt{10}+20$

$38+12\sqrt{10}$