Question

find the square of: 3a-2b-5c​

Answer 1

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Step-by-step explanation:

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Answer 2

Given equation is,

$3a-2b-5c$

Now we have to find the square of the given equation.

We get,

$(3a-2b-5c)^{2}$

The above equation is in the form of

$(a-b-c)^{2}$

Formula for $(a-b-c)^{2}$

$(a-b-c)^{2}=a^{2}+b^{2}+c^{2}-2ab+2bc-2ca$

Here,

$a=3a$

$b=2b$

$c=5c$

Substitute these values in the formula.

We get,

$(3a-2b-5c)^{2}=(3a)^{2}+(2b)^{2} +(5c)^{2} -2(3a)(2b)+2(2b)(5c)-2(5c)(3a)$

$(3a-2b-5c)^{2} =9a^{2} +4b^{2} +25c^{2} -12ab+20bc-30ca$

Therefore, the square of $3a-2b-5c$ is $9a^{2} +4b^{2} +25c^{2} -12ab+20bc-30ca$