find the square of 3n,3n+1 and,3n+2
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Answered by
1
Hey bro hope it helps u
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Answered by
1
Step-by-step explanation:
Therefore arithmetic mean is given by
n
1+3+3
2
+...+3
n−1
Sum of n terms of a geometric progression with a being the first term and r as the common ratio is given by
r−1
a(r
n
−1)
Here, a=1 and r=3
∴ arithmetic mean =
(3−1)n
1×(3
n
−1)
∴ arithmetic mean =
2n
3
n
−1
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