find the square of 42 by coloum method
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Answered by
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Answer:
(a+b)^2=a^2+2ab+b^2
=(42=40+2)
=(40+2)^2=(40)^2+2(40)(2)+(2)^2
=1600+160+4
=(42)^2=1764
Step-by-step explanation:
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Answered by
0
Answer:
Solution:
We know that
$$\begin{lgathered}( {a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} \\ \\ here \\ 42 = 40 + 2 \\ \\ {(40 + 2)}^{2} = ( {40)}^{2} + 2(40)(2) + {2}^{2} \\ \\ = 1600 + 160 + 4 \\ \\ ( {40)}^{2} = 1764 \\ \\\end{lgathered}$$
put those values in the column,while writing the answer
Hope it helps you.
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