find the square of 4a + 3b
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- Given Equation is (4a - 3b)^2.
- It is in the form of (a - b)^2 = a^2 + b^2 - 2ab.
- = > (4a)^2 + (3b)^2 - 2(4a)(3b)
- = > 16a^2 + 9b^2 - 24ab.
- Hope this helps!
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Answers:-
(4a+3b)^2=16a^2+24ab+9b^2
Step-by-step explanation:
(a+b)^2=a^2+2ab+b^2
(4a+3b)^2=(4a)^2+2×4a×3b+(3b)^2
(4a+3b)^2=16a^2+24ab+9b^2.
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