Question

Find the square of (4a-3b+3c)​

Answer 1

Answer:

Step-by-step explanation:

(4a-3b+3c)​^2 =  

(4a)^2 + (-3b)^2 + (3c)^2 + 2(4a)(-3b) + 2(-3b)(3c) + 2(3c)(4a)

= 16a^2 + 9b^2 + 9c^2  -24ab -18bc + 24ca  

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