Math, asked by st479723, 1 day ago

find the square of (√5a+√6b)



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Answers

Answered by Dalfon
30

Answer:

5a² + 6b² + 2ab√30

Step-by-step explanation:

We need to find out the square of (√5a + √6b).

→ (√5a + √6b)²

Used formula: (a + b)² = a² + b² + 2ab

→ (√5a)² + (√6b)² + 2(√5a)(√6b)

Root can be written as ½. Also we need to do the square. So, now powers are expressed as (2 × 1/2) which means 1.

→ 5a² + 6b² + 2ab√30

Therefore, the value of (√5a + √6b)² is 5a² + 6b² + 2ab√30.

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ADDITIONAL INFORMATION:

Let's take more examples to solve such type of

questions.

1) 4 - 2(√2)². In this square is only on √2 and we already know that root means 1/2, so on solving power we get 2.

→ 4 - 2(2)

→ 4 - 4

→ 0

Value of 4 - 2(√2)² is 0.

2) (√5 + √3)/(√5 - √3) such type of questions are solved by rationalisig the denominator (whenever we do rationalise, we use opposite sign, that of the given sign in denominator).

→ (√5 + √3)/(√5 - √3) (√5+ √3)/(√5 + √3)

→ [√5(√5 + √3) + √3(√5 + √3)]/[(√5 - √3)(√5 + √3)]

Used formula: (a + b) (a - b) = a² - b²

→ (5 + √15 + √15 + 3)/(5 - 3)

→ (8 + 2√15)/2

→ 4 + √15

Answered by singhchandraprabha99
0

A

Step-by-step explanation:

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