Question

Find the square of (7x-y/3)

Answer 1

Answer:

$49x^2 + y^2 - 14xy/9$

Step-by-step explanation:

$(7x-y/3)^2\\ (7x-y)^2/9\\\ [ using (a-b)^2 = a^2 + b^2 - 2ab ]\\49x^2 + y^2 - 2(7x)(y)/9\\49x^2 + y^2 - 14xy/9$

Hope it helps...