Question

find the square of 95 using algebraic identity.​

Answer 1

Solution:

95²

⟹ (100 - 5)²

⟹ (100)² + (5)² - 2 × 100 × 5

⟹ 10000 + 25 - 2 × 500

⟹ 10025 - 1000

⟹ 9025

$\therefore$Square of 95 = 9025

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$\boxed{\begin{minipage}{7 cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\sf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\sf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\sf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8)\sf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\\end{minipage}}$

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Answer 2

Answer:

(95)²= (100-5)²

100²-2×100×5+5²

10000-1000+25

9025