Question

Find the square of:
(a)(2x-1/x)
(b)3z-1/z
(c) a²b-b²a
(d) (1.5²+0.3²)​

Answer 1

Answer:

2x-1/x = 3

3z-1/z = 8

a^2b-b^2a = a-b

1.5^2+0.3^2 = 2.34

Step-by-step explanation:

(2x-1/x)^2 = 4x^2 - 1/x^2

x^2 cut by x^2

4-1 = 3

(3z-1/z)^2 = 9-1=8

a^2b - b^2a = a^2b - b^2a

a-b

(1.5^2 - 0.3^2)

= 2.25 + 0.09

= 2.34

Answer 2

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