Find the square of a number 46 by using squ
are identity.
Answers
Step-by-step explanation:
Let:−
Find the square of a number 46 by using squ
are identity.
\sf{\implies The\: number\:_{(correct\:question)}=x}⟹Thenumber
(correctquestion)
=x
\sf{\implies The\: number\:_{(wrong\:question)}=x}⟹Thenumber
(wrongquestion)
=x
\sf\large\underline{To\:Find:-}
ToFind:−
\sf{\implies The\: number\:_{(correct\:question)}=?}⟹Thenumber
(correctquestion)
=?
\sf\large\underline{Solution:-}
Solution:−
To calculate the number of correct question which is given by Herman at first we have to focus on the given Question after that we have to set up equation then solve the equation by solving we get the number of correct question.
\sf{\implies Calculation\:for\:1st\:equation:-}⟹Calculationfor1stequation:−
\sf{\implies Number\:_{(correct\:Q)}-1=Number\:_{(wrong\:Q)}}⟹Number
(correctQ)
−1=Number
(wrongQ)
\tt{\implies x-1=y}⟹x−1=y
\tt{\implies x-y=1---(i)}⟹x−y=1−−−(i)
\sf{\implies Calculation\:for\:2nd\:equation:-}⟹Calculationfor2ndequation:−
\sf{\implies mark\:_{(correct\:Q)}-mark\:_{(wrong\:Q)}=Total\:_{(marks)}}⟹mark
(correctQ)
−mark
(wrongQ)
=Total
(marks)
\tt{\implies 4x-y=40-----(ii)}⟹4x−y=40−−−−−(ii)
In eq (i) multiply by 4 then subract from (ii):-]
\tt{\implies 4x-4y=4}⟹4x−4y=4
\tt{\implies 4x-y=40}⟹4x−y=40
By solving we get here:-]
\tt{\implies -3y=-36}⟹−3y=−36
\tt{\implies y=12}⟹y=12
Putting the value of y=12 in eq (i):-]
\tt{\implies x-y=1}⟹x−y=1
\tt{\implies x-12=1}⟹x−12=1
\tt{\implies x=1+12}⟹x=1+12
\tt{\implies x=13}⟹x=13
\sf\large{Hence,}Hence,
\sf{\implies The\: number\:_{(correct\:question)}=13}⟹Thenumber
(correctquestion)
=13
Answer:
46 don't have a square
following this method you can get the answer
