Question

Find the square of (i) (a-2b) (ii) (3c + 5 d)​

Answer 1

Answer:

(a-2b)^2= a^2+4b^2-4ab

div by ab on both sides,

a/b+4b/a=4.

2.(3c+5d)^2=9c^2+25d^2+30cd

9c^2+25d^2=-30cd

divide by cd on both sides,

9c/d+25d/c=-30.