Math, asked by Anonymous, 2 months ago

Find the square of:
(i) (root 7+3)
(ii) (root 5- root 3)
(iii) (4+2 root 3)
(iv) (6-3 root 2)
(v) (11-3 root 3)

Answers

Answered by chiggi2k03
1

Answer:

1) √7 + 3 =  (√7 + 3)²

              = 7 + 9 + 2(√7)(3)

            = 16 + 6√7

2)  √5 - √3 = (√5 - √3)²

                 = 5 + 3 - 2(√5)(√3)

                = 8 - 2√15

3)  4 + 2√3  = (4 + 2√3)²

                    = 16 + 12 + 2(4)(2√3)

                   =  28 + 16√3

4)  6 - 3√2   = (6 - 3√2)²

                    =  36 + 18 - 2(6)(3√2)

                   =  54 - 36√2

5)  11 - 3√3  =  (11 - 3√3)²

                    = 121 + 27 - 2(11)(3√3)

                    =  148 - 66√3

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