Find the Square of:
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(3+2√5)^2=9+20+12√5=29+12√5
is your answer
is your answer
Answered by
1
(3+2√5)^2
=(3)^2+2(3)(2√5)+(2√5)^2[applying identity of (a+b)^2=a^2+2ab+b^2
=9+12√5+20
=29+12√5
If you find it helpful please mark it as brainliest....
=(3)^2+2(3)(2√5)+(2√5)^2[applying identity of (a+b)^2=a^2+2ab+b^2
=9+12√5+20
=29+12√5
If you find it helpful please mark it as brainliest....
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