find the square of
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(5x +2y)^2
(5x)^2+2×5x×2y+(2y)^2
25x^2+20xy+4y^2
(5x)^2+2×5x×2y+(2y)^2
25x^2+20xy+4y^2
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Answer:
Step-by-step explanation:
squaring first equation
(5x-2y)^[2]=[7]^2
25x^[2]+ 4y^[2] - 20xy=49
25x^[2]+ 4y^[2] - 20{2]=49
25x^2+ 4y^[2] = 49 - 40
25x^[2] + 4y^[2] = 9
now
(5x+2y)^[2]=25x^[2]+4y^[2]+20xy
putting the values found above
9+20{2}
║49║
PLEASE MARK BRAINLIEST
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