Question

find the square of =
$\sqrt{3} +\sqrt{2}$

Answer 1

Using identity (a + b)² = a² + b² + 2ab

=>
$( \sqrt{3} + \sqrt{2} ) {}^{2} \\ = 3 + 2 + 2 \times \sqrt{3} \times \sqrt{2} \\ = 5 + 2 \sqrt{6}$
5 + 2√6 is your answer


Hope it helps dear friend ☺️✌️

Answer 2

$\textbf{Answer:}$

We use the following identity ↓

【(a + b)² = a² + 2ab + b²】

➡ (√3 + √2)²

$= ( \sqrt{3} ) {}^{2} + 2( \sqrt{3} )( \sqrt{2} ) + ( \sqrt{2} ) {}^{2}$

$= 3 + 2 \sqrt{6} + 2$

$= 5 + 2 \sqrt{6}$
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