Question

find the square of the distance between the pints A( 2, 4 ) and B (-1,5)

Answer 1

Distance AB is given by

$= \sqrt{(5 - 4) {}^{2} + ( - 1 - 2) {}^{2} }$

$= \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$= \sqrt{1 + 9}$

$= \sqrt{10}$

Square of distance AB :

$= ( \sqrt{1 0} ) {}^{2}$

$= 10$