Question

Find the square of the following by using identity (b-7)2

Answer 1

$b^2-14b+49$ is the square.

Step-by-step explanation:

Since we have given that

$(b-7)^2$

As we know the identity :

$(a-b)^2=a^2+b^2-2ab$

So, it becomes,

$(b-7)^2=b^2+7^2-2\times 7\times b\\\\(b-7)^2=b^2+49-14b$

Hence, $b^2-14b+49$ is the square.

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Find square by using identities: (b-7)^2

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Answer 2

Step-by-step explanation:

Since we have given that

(b-7)^2(b−7)

2

As we know the identity :

(a-b)^2=a^2+b^2-2ab(a−b)

2

=a

2

+b

2

−2ab

So, it becomes,

\begin{gathered}(b-7)^2=b^2+7^2-2\times 7\times b\\\\(b-7)^2=b^2+49-14b\end{gathered}

(b−7)

2

=b

2

+7

2

−2×7×b

(b−7)

2

=b

2

+49−14b