Question

find the square of the following numbers.

1) 32
2) 86​

Answer 1

⭐️Solution⭐️

$1) \: \huge \: 32$

${(32)}^{2} = {(30 + 2)}^{2}$

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

$here \: a = 30 \: and \: b = 2$

${(30 + 2)}^{2} = {(30)}^{2} + 2 \times 30 \times 2 + {(2)}^{2}$

${30}^{2} = 900 + 120 + 4$

$32 = 1024$

$2) \huge \: 86$

${(86)}^{2} = {(80 + 6)}^{2}$

${(a + b)}^{2} = {a}^{2} + 2ab + b$

$here = a = 80 \: and \: b = 6$

${(80 + 6}^{2} = {(80)}^{2} + 2 \times 30 \times 6 + {(6)}^{2}$

$86 = 6400 + 960 + {(6)}^{2}$

$86 = 7396$