History, asked by pjagu2101, 1 month ago

Find the square of the following numbers. 1.48 2. 56 3. 85 4. 372 5. 216​ answer me fast plz plz i want faster that I can who will give me first answer i will give him 5 stat, like and mark as Brainlist​

Answers

Answered by raginikumari37316
4

Answer:

  1. The square root of 48 is 4√3.
  2. The square root of 56 is the irrational number with approximate value 7.48331 and exact value 2√(14).
  3. square root of 85 9.21954445729
  4. square root of 372 19.287301522
  5. square root of 216 14.6969384567
Answered by sgokul8bkvafs
0

Answer:

Explanation:

Q1) Find the square of the following numbers.

(i) 32

(ii) 35

(iii) 86

(iv) 93

(v) 71

(vi) 46

Solution

Transcript

Solution:

(i)

\left(32\right)^2=\left(30+2\right)^2=\left(30\right)^2+2\times30\times2+\left(2\right)^2(32)  

2

=(30+2)  

2

=(30)  

2

+2×30×2+(2)  

2

 

[\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b)  

2

=a  

2

+2ab+b  

2

]

= 900 + 120 + 4 = 1024

(ii) \left(35\right)^2=\left(30+5\right)^2=\left(30\right)^2+2\times30\times5+\left(5\right)^2(35)  

2

=(30+5)  

2

=(30)  

2

+2×30×5+(5)  

2

 

[\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b)  

2

=a  

2

+2ab+b  

2

 

= 900 + 300 + 25 = 1225

(iii) \left(86\right)^2=\left(80+6\right)^2=\left(80\right)^2+2\times80\times6+\left(6\right)^2(86)  

2

=(80+6)  

2

=(80)  

2

+2×80×6+(6)  

2

 

[\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b)  

2

=a  

2

+2ab+b  

2

 

= 8100 + 540 + 9 = 8649

(iv) \left(93\right)^2=\left(90+3\right)^2=\left(90\right)^2+2\times90\times3+\left(3\right)^2(93)  

2

=(90+3)  

2

=(90)  

2

+2×90×3+(3)  

2

 

[\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b)  

2

=a  

2

+2ab+b  

2

]

= 8100 + 540 + 9 = 8649

(v) \left(71\right)^2=\left(70+1\right)^2=\left(70\right)^2+2\times70\times1+\left(1\right)^2(71)  

2

=(70+1)  

2

=(70)  

2

+2×70×1+(1)  

2

 

[\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b)  

2

=a  

2

+2ab+b  

2

 

= 4900 + 140 + 1 = 5041

(vi) \left(46\right)^2=\left(40+6\right)^2=\left(40\right)^2+2\times40\times6+\left(6\right)^2(46)  

2

=(40+6)  

2

=(40)  

2

+2×40×6+(6)  

2

 

[\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b)  

2

=a  

2

+2ab+b  

2

]

= 1600 + 480 + 36 = 2116

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