Question

Find the square of the following numbers using
the identity
$(a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2}$
(a) 208 , (b) 512 , (c) 635​

Answer 1

Answer:

(208)²=(200+8)²=200²+2×200×8+8²

=40000+3200+64=43264

Answer 2

(a) (208)²=

(200+8)²=200²+2×200×8+8²

=40000+3200+64

=43264

(b) (512)²=(500+12)²=500²+2×500×12+12²

=250000+12000+144

=262144

(c) (635)²= (600+35)²= 600²+2×600×35+35²

=360000+42000+1225

=403225