Question

Find the square of the following numbers using the identity (a-b) ²=a²-2ab+b²:
1) 491^2

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Answer 1

Step-by-step explanation:

(500-9)^2=(500)^2-2×500×9+(9)^2

=250000-9000+81

= 250081-9000

= 241081

Answer 2

$\huge{\bf{\purple{\underline{\underline{\colorbox{lavender}{\color{purple}{Solution:}}}}}}}$

We have,

$\: \: \: \: \: \longrightarrow \: \: \sf\boxed{491^{2} = (500 - 9)^{2} }$

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$\implies500 ^{2} - 2 \times 500 \times 9 + 9^{2}$

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$\implies250000 - 9000 + 81$

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$\bf{ \implies \color{magenta}\boxed{ \green{241081}}}$

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