Question

find the square of the following using identity 55, 98​

Answer 1

Step-by-step explanation:

1) 55 can be written as (50+5)

55^2= (50+5)^2= (50+5) (50+5)

We know the identity (a+b)^2= a^2+b^2+2ab

=> 50^2+2×50×5+5^2

=> 2500+500+25= 3025

=> (55)^2= 3025

2) 98 can be written as (90+8)

98^2= (90+8)^2= (90+8) (90+8)

We know the identity (a+b)^2 =a^2+b^2+2ab

=> 90^2+2×90×8+8^2

=> 8100+1440+64= 9604

=> (98)^2= 9604