Question

Find the square of (x-3)
with process please answer this

Answer 1

$\textsf{\large{\underline{Solution}:}}$

We have to evaluate the square of (x - 3)²

$\rm = {(x - 3)}^{2}$

Using identity (a - b)² = a² - 2ab + b², we get:

$\rm = {x}^{2} - 2 \times x \times 3 + {3}^{2}$

$\rm = {x}^{2} - 6x + 9$

Therefore:

$\rm: \longmapsto{(x - 3)}^{2} = {x}^{2} - 6x + 9$

★ Which is our required answer.

$\textsf{\large{\underline{More To Know}:}}$

• (a + b)² = a² + 2ab + b²
• (a - b)² = a² - 2ab + b²
• a² - b² = (a + b)(a - b)
• (a + b)³ = a³ + 3ab(a + b) + b³
• (a - b)³ = a³ - 3ab(a - b) - b³
• a³ + b³ = (a + b)(a² - ab + b²)
• a³ - b³ = (a - b)(a² + ab + b²)
• (x + a)(x + b) = x² + (a + b)x + ab
• (x + a)(x - b) = x² + (a - b)x - ab
• (x - a)(x + b) = x² - (a - b)x - ab
• (x - a)(x - b) = x² - (a + b)x + ab

Answer 2

$\huge \blue{ \boxed{ \bf \color{lime}{ {x}^{2} - 6x + 9}}}$

Step-by-step explanation:

QUESTION :-

Find the square of (x - 3).

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SOLUTION :-

The square of (x - 3)

$\bf = > {(x - 3)}^{2}$

$\bf = > {x}^{2} - (2 \times x \times 3) + {( 3)}^{2} .... \tiny \{using \: identity \: {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \}$

$\bf = > \underline \red{ {x}^{2} - 6x + 9}$

Hence,

The square of (x - 3) is x² - 6x + 9.

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MORE TO KNOW :-

• (a + b)² = a² + 2ab + b²
• a² - b² = (a + b)(a - b)
• a² + b² = (a + b)² - 2ab
• a² + b² = (a - b)² + 2ab
• (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)
• (a + b)³ = a³ + b³ + 3ab(a + b)
• (a - b)³ = a³ - b³ - 3ab(a - b)
• (x + a)(x + b) = x² + (a + b)x + ab
• a³ + b³ = (a + b)(a² - ab + b²)
• a³ - b³ = (a - b)(a² + ab + b²)

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Hope it helps.

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