Question

find the square root by repeated subtraction method of 121

Answer 1

121-1=120 (step 1)
120-3=117 (step 2)
117-5=112 (step 3)
112-7=105 (step 4)
105-9=96 (step 5)
96-11=85 (step 6)
85-13=72 (step 7)
72-15=57 (step 8)
57-17=40 (step 9)
40-19=21 (step 10)
21-21=0 (step 11)

Therefore 121 is the sure root of 11

Answer 2

$subtraction \: method \: of \: 121 \\ \\ steps \: 1 \: \: \: 121 - 1 = 120 \\ steps \: 2 \: \: \: \: 120 - 3 = 117 \\ steps \: 3 \: \: \: 117 - 5 = 112 \\ steps \: 4 \ \ \: 112 - 7 = 105 \\steps \: 5 \: \: \: 105 - 9 = 96 \\steps \: 6 \: \: \: \: 96 - 11 = 85 \\steps \: 7 \: \: \: 85 - 13 = 72 \\ steps \: 8 \: \: \: 72 - 15 = 57 \\steps \: 9 \: \: \: 57 - 17 = 40 \\steps \: 10 \: \: 40 - 19 = 21 \\steps \: 11 \: \: 21 - 21 = 0 \\ therefore \: \sqrt{121} = 11 \: in \: steps \: \\ plz \: mark \: me \: as \: brainliest \\ plz \: follow \: me \\ dfgh$