find the square root by the repeated subtraction. 144 and 676
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Question :- find the square root by the repeated subtraction :- 144 and 676 ?
Concept :-
- we have subtracted consecutive odd numbers from 1 till we get 0.
Solution :-
Square root of 144 :-
- 144 - 1 = 143
- 143 - 3 = 140
- 140 - 5 = 135
- 135 - 7 = 128
- 128 - 9 = 119
- 119 - 11 = 108
- 108 - 13 = 95
- 95 - 15 = 80
- 80 - 17 = 63
- 63 - 19 = 44
- 44 - 21 = 23
- 23 - 23 = 0 .
Therefore, we have subtracted consecutive odd numbers from 144 starting from 1. 0 is obtained in the 12th step.
Hence, Square root of 144 is 12.
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Square root of 676 :-
- 676 - 1 = 675
- 675 - 3 = 672
- 672 - 5 = 667
- 667 - 7 = 660
- 660 - 9 = 651
- 651 - 11 = 640
- 640 - 13 = 627
- 627 - 15 = 612
- 612 - 17 = 595
- 595 - 19 = 576
- 576 - 21 = 555
- 555 - 23 = 532 .
- 532 - 25 = 507
- 507 - 27 = 480
- 480 - 29 = 451
- 451 - 31 = 420
- 420 - 33 = 387
- 387 - 35 = 352
- 352 - 37 = 315
- 315 - 39 = 276
- 276 - 41 = 235
- 235 - 43 = 192
- 192 - 45 = 147
- 147 - 47 = 100
- 100 - 49 = 51
- 51 - 51 = 0 .
Therefore, we have subtracted consecutive odd numbers from 676 starting from 1. 0 is obtained in the 26th step.
Hence, Square root of 676 is 26.
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