Question

find the square root for 16x^4+8x^2+1​

Answer 1

Answer:

answer is 4x+1

Step-by-step explanation:

firstly simplifying the expression:

$16 {x}^{4} + 8 {x}^{2} + 1$

${(4x)}^{2} + 2 \times 4x \times 1 + {1}^{2}$

we know that:

a^2+2ab+b^2=(a+b)^2

so it can be written as:

${(4x + 1)}^{2}$

now finding square root of it,we get

$\sqrt{ {(4x + 1)}^{2} }$

$= 4x + 1$

PLEASE MARK MY ANSWER AS BRAINLIEST AND THANK ME.

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

We have to find the square root of : 16x⁴ + 8x² + 1.

We will square root to the polynomial.

So, A.T.Q

$\sf{→\sqrt{16x^4 + 8x^2 + 1}} \\ \\ \bf{\gray{We \: can \: write \: 16x^4 \: as (4x^2)}} \\ \\ \sf{→\sqrt{(4x)^2 + 8x^2 + 1}} \\ \\ \bf{\gray{We \: can \: write \: 8x^2 \: as \: 2(4x)(1) \: and \: 1 \: as \: 1^2}}\\ \\ \sf{→\sqrt{(4x)^2 + 2(4x)(1) + 1^2}} \\ \\ \large{\implies{\boxed{\boxed{\sf{(a + b)^2 = a^2 + b^2 + 2ab}}}}}\\ \\ \sf{→\sqrt{(4x + 1)^2}}\\ \\ \sf{4x + 1} \\ \\ \large{\implies{\boxed{\boxed{\sf{(4x + 1)}}}}}$