Find the square root of 1.1 upto 2 decimal places
Answers
Step-by-step explanation:
Answer:-
The Length Of The Ladder Is 10 m.
Explanation:-
Given:-
Distance between the foot of the ladder and the wall (AB) = 8 m.
Height of the window (AC) = 6 m.
ToFind:-
The length of ladder.
Theorem Used:-
Pythagoras Theorem:- In a right angle triangle Square of Hypotenuse is equal to the sum of the square of its base and height.
\begin{gathered}\\ \large\bf\longrightarrow H^2 = P^2 + B^2.\end{gathered}
⟶H
2
=P
2
+B
2
.
Where,
H = Hypotenuse.
P = Perpendicular I.e. height.
B = Base.
So Here,
H = Length Of ladder = ?? [To Find].
P = AC = 6 m.
B = AB = 8 m.
Now,
By Applying Pythagoras Theorem,
\begin{gathered}\\ \bf\mapsto H^2 = P^2 + B^2.\end{gathered}
↦H
2
=P
2
+B
2
.
\begin{gathered}\\ \tt\mapsto H {}^{2} = (6 \: m) {}^{2} + (8 \: m) {}^{2} .\end{gathered}
↦H
2
=(6m)
2
+(8m)
2
.
\begin{gathered}\\ \tt\mapsto H = \sqrt{36 \: m {}^{2} + 64 \: m {}^{2} } .\end{gathered}
↦H=
36m
2
+64m
2
.
\begin{gathered}\\ \tt\mapsto H = \sqrt{100 \: m {}^{2} }\end{gathered}
↦H=
100m
2
\begin{gathered}\\ \tt\mapsto H = \sqrt{10 \times 10} \: \: m .\end{gathered}
↦H=
10×10
m.
\begin{gathered}\\ \large\bf\mapsto H = 10 \: m.\end{gathered}
↦H=10m.
Therefore The Length Of The Ladder Is H = 10m.
Answer:
answer for the given problem is given
