Find the square root of 1-7i
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Answer
Let
−7+24i
=x+iy
On squaring, we get
−7+24i=(x
2
−y
2
)+2ixy
Equating the real and imaginary parts
x
2
−y
2
=−7 and 2xy=24
x
2
+y
2
=
(x
2
−y
2
)+4x
2
y
2
=
(−7)
2
+(24)
2
=25
Solving, x
2
−y
2
=−7 and x
2
+y
2
=25
we get x
2
=9 and y
2
=16
∴x=±3 and y=±4
Since xy is positive, x and y have the same sign.
∴(x=3,y=4) or (x=−3,y=−4)
∴
−7+24i
=(3+4i) or (−3−4i)
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