Math, asked by L1296, 9 days ago

Find the square root of 10+2√6+√15+2√10​

Answers

Answered by srps915
1

Answer:

Supposing you wanted to write 2√6, 2√10, 2√15, the square root would be (√2+√3+√5).

10+ 2√6+2√10+2√15

=10+2√2*√3+2√2*√5+2√3*√5

=(√2)^2+(√3)^2+(√5)^2+2√2*√3+2√2*√5+2√3*√5

Comparing with the form (a^2+b^2+c^2+2ab+2bc+2ca)=(a+b+c)^2

We get the square root as (√2+√3+√5)

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