Find the square root of 11+2root30
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5
Answer:
± ( √5 + √6 )
Step-by-step explanation:
We need to find a and b such that...
( a + b√30 )² = 11 + 2√30.
Expanding gives
( a² + 30b² ) + 2ab√30 = 11 + 2√30
so we need...
ab = 1 and a²+30b² = 11.
⇒ a² + 30/a² = 11
⇒ a⁴ - 11a² + 30 = 0
⇒ ( a² - 5 ) ( a² - 6 ) = 0.
For one solution (we only need one, not all!), take a = √5. Then b = 1/√5.
So a square root of 11 + 2√30 is
a + b√30
= √5 + √30/√5
= √5 + √6.
There are two square roots, and the other is just minus this one.
Hope this helps!
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