Question

Find the square root of 25, 49, 121 and 196

Answer 1

5of 25
7of 49
11of 121

Answer 2

I will try my best to give the solution in most detailed manner such that you will be able to understand the solutions quickly ,as well as you will be able to build logic if question’s of these types are asked in future .

That’s enough talk, Let’s start!

Step 1: Initially try to read the question , and think about what all changes are made in each digits as we are moving forward .

Step 2: As you will see that all the digits are square’s of digits , after analysing it once again , you will get that the given digits are squares of odd digits.

Step 3: And we can write odd digits in one more form (2*n+1). But those above digits are square of odd numbers so instead we will write as (2*n+1)^2.

Step 4: So now we just need to substitute values in place of n.

So for n=0,we get (2*0+1)^2=1

for n=1 ,we get (2*1+1)^2=9

for n=2,we get (2*2+1)^2=25