Question

find the square root of (2xsquare+8ysquare)whole square+(2xsquare-8ysquare)whole square​

Answer 1

Answer:

Step-by-step explanation:

(2x^2+8y^2)^2+(2x^2-8y^2)^2

=((2x^2)^2+(8y^2)^2+2x2x8)+((2x^2)^2+(8y^2)^2-2x2x8)

=(4x^4+16y^4+32)+(4x^4+16y^4-32)

=4x^4+16y^4+32+4x^4+16y^4-32